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Sciences 21 Mar 2025 · 7 min read

HSC Chemistry Module 6: Your Complete Guide to Acids and Bases

Module 6 builds directly on everything you learned in equilibrium. If you understood Module 5, acid-base chemistry is simply applying those same principles to proton transfer reactions.

Here is something most students do not realise until too late: Module 6 is not a brand-new topic. It is Module 5 wearing a lab coat. Almost every concept in acid-base chemistry, from Ka values to buffer systems, is an application of equilibrium. If you built a strong foundation in Module 5, this module should feel like a natural extension. If you did not, this is where the gaps start showing.

Let's walk through every major concept you need, in the order that makes the most sense for building understanding.

Bronsted-Lowry Theory

The HSC uses the Bronsted-Lowry definition of acids and bases. An acid is a proton (H+) donor. A base is a proton acceptor. This is more useful than the older Arrhenius definition because it works in solvents other than water and explains reactions between gases.

Every Bronsted-Lowry acid-base reaction involves a conjugate pair. When an acid donates a proton, it becomes its conjugate base. When a base accepts a proton, it becomes its conjugate acid. For example:

HCl(aq) + H2O(l) ⇌ Cl-(aq) + H3O+(aq)

Here, HCl is the acid and H2O is the base. After the proton transfer, Cl- is the conjugate base of HCl, and H3O+ is the conjugate acid of H2O.

You also need to understand amphiprotic substances. Water is the classic example. It can act as an acid (donating H+ to form OH-) or as a base (accepting H+ to form H3O+). Amino acids are another important example. The HSC loves asking students to identify amphiprotic species and write equations showing both behaviours.

Strong vs Weak Acids and Bases

This is where equilibrium thinking becomes essential. A strong acid ionises completely in water. Every molecule of HCl that dissolves produces an H+ and a Cl-. There is no equilibrium to speak of because the reaction goes to completion. A weak acid only partially ionises. Acetic acid (CH3COOH), for instance, establishes an equilibrium where most molecules remain un-ionised at any given time.

The strength of a weak acid is quantified by its acid dissociation constant, Ka. A larger Ka means more ionisation and a stronger weak acid. A smaller Ka means less ionisation. This is the same logic as Keq from Module 5, just applied specifically to acid ionisation.

Important: strength and concentration are not the same thing. You can have a concentrated weak acid or a dilute strong acid. Strength refers to the degree of ionisation. Concentration refers to how much solute is dissolved per litre.

pH Calculations You Need to Master

The pH scale quantifies the acidity or basicity of a solution. The core formulas are straightforward, but the HSC expects you to apply them fluently across different scenarios.

Essential pH Formulas

pH = -log10[H+] and [H+] = 10-pH

pOH = -log10[OH-] and pH + pOH = 14 (at 25°C)

Kw = [H+][OH-] = 1.0 x 10-14 (at 25°C)

For strong acids: [H+] equals the concentration of the acid (complete ionisation). For weak acids: use Ka and an ICE table to find [H+].

Dilution calculations also come up frequently. When you dilute an acid, you are reducing the concentration of H+ ions, which increases the pH. For a strong acid, a tenfold dilution increases pH by exactly 1. For a weak acid, the increase is less than 1 because the equilibrium shifts to produce more H+ as you dilute.

The HSC also expects you to know that Kw changes with temperature. At temperatures above 25°C, Kw increases because the autoionisation of water is endothermic. This means neutral pH is no longer 7 at higher temperatures.

Titrations and Titration Curves

A titration is a quantitative analytical technique where you add a solution of known concentration (the titrant) to a solution of unknown concentration (the analyte) until the reaction reaches its equivalence point. The shape of the titration curve tells you almost everything about the reaction.

TITRATION CURVE: WEAK ACID + STRONG BASE pH Volume of NaOH added (mL) 0 2 4 6 8 10 12 25 mL Equivalence point 12.5 mL pH = pKₐ Buffer region

For a strong acid + strong base titration, the equivalence point is at pH 7. The curve is steep and symmetrical around the equivalence point. For a weak acid + strong base titration (like acetic acid with NaOH), the initial pH is higher than you would expect for the same concentration of a strong acid, the curve rises more gradually, and the equivalence point is above pH 7. This is because the conjugate base of the weak acid is itself a weak base, making the solution slightly basic at the equivalence point.

The half-equivalence point is where exactly half the acid has been neutralised. At this point, [HA] = [A-], which means pH = pKa. This is a very common exam question.

Choosing the right indicator is about matching the indicator's colour change range (its transition range) with the pH at the equivalence point. For a strong acid + strong base titration, almost any indicator works because the pH jump is so steep. For a weak acid + strong base titration, you need an indicator that changes colour in the basic range (pH 8 to 10), like phenolphthalein.

Buffers

A buffer solution resists changes in pH when small amounts of acid or base are added. It is made from a weak acid and its conjugate base (or a weak base and its conjugate acid) in roughly similar concentrations.

The mechanism is elegant. If you add H+ to a buffer, the conjugate base (A-) reacts with those H+ ions to form the weak acid (HA), consuming the added acid before it can significantly change the pH. If you add OH-, the weak acid (HA) donates a proton to the OH-, forming water and the conjugate base, again preventing a major pH shift.

The relationship between pH, pKa, and the ratio of conjugate base to acid is described by the Henderson-Hasselbalch equation:

pH = pKa + log10([A-] / [HA])

When [A-] = [HA], the log term equals zero, and pH = pKa. This is why buffers are most effective when the pH is close to the pKa of the weak acid being used. Biological systems rely heavily on buffer chemistry. Blood is buffered by the carbonic acid/bicarbonate system at around pH 7.4.

Exam Tips for Module 6

Module 6 questions are predictable in structure, but the examiners are very particular about how you express your answers. Here is what they look for.

  1. Always write the ionic equation. If a question asks you to explain an acid-base reaction, write the equation showing the proton transfer. Molecular equations are not sufficient for Bronsted-Lowry questions. Identify the acid, base, conjugate acid, and conjugate base explicitly if asked.
  2. Explain indicator choice properly. Do not just say "phenolphthalein is suitable." Say that the equivalence point occurs in the basic pH range (e.g. pH 8.7), and phenolphthalein transitions between pH 8.2 and 10, which encompasses the equivalence point. The transition range must overlap with the steep section of the titration curve.
  3. Link back to equilibrium. When explaining why a weak acid has a higher pH than a strong acid at the same concentration, reference the equilibrium that exists for the weak acid. The incomplete ionisation means fewer H+ ions in solution, therefore a higher pH.
  4. Be precise with Kw and temperature. If a question mentions a temperature other than 25°C, do not assume Kw = 1.0 x 10-14. State that Kw changes with temperature and use the value provided.
  5. Show your ICE table for weak acid pH calculations. Even if you can do it in your head, the working is worth marks. Write the equilibrium expression, substitute, and solve step by step.

Module 6 is one of the most calculation-heavy modules in HSC Chemistry, but every calculation is grounded in the equilibrium principles you already know. If you can connect the dots between Ka, Kw, and Le Chatelier's Principle, the whole module becomes a coherent system rather than a list of disconnected formulas.

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